Detailed Explanation of Calculation Methods for Installing Fans and Cooling Pads in Chicken Houses
Calculation Methods for Installing Fans and Cooling Pads in Chicken Houses
Calculation methods for installing fans and cooling pads in chicken houses (the following is a hypothetical example)
1. Chicken house area: 120 m * 12 m = 1440 sq m
2. Chicken house cross-sectional area: 12 m * (height) 2.5 m = 30 sq m
3. Maximum total rearing weight in the chicken house: 1440 sq m * 12 birds/sq m * 2.5 kg/bird = 43200 kg
4. Required maximum ventilation rate: 43200 kg * 9 cubic meters per kg per hour = 388800 cubic meters
5. Number of fans required: 388800 cubic meters (divided by) assuming 43000 cubic meters per fan = 9 fans The ventilation rate of fans varies by model and manufacturer, so calculate according to actual fan parameters. Depending on the size of the chicken house, 1-3 backup fans need to be added. This chicken house needs at least 3 additional fans, so a total of 12 fans are required
6. Maximum air speed inside the house: 388800 cubic meters (divided by) 3600 seconds (divided by) cross-sectional area 30 sq m = 3.6 m per second
7. Cooling pad calculation: for 15 cm thickness, the required air speed through the pad is 1.5-2 m per second If the thickness is 10 cm, calculate the air speed through the pad as 1-1.5 m per second
8. Required cooling pad area: 388800 cubic meters (divided by) 3600 seconds (divided by) 1.5-2 m per second = 54—72 sq m Generally the median value is taken, requiring about 64 sq m of cooling pad area
9. The above calculation concerns negative pressure and the air leakage coefficient of the chicken house walls. With additional backup fans, it is sufficient.
10. The ventilation rate per kg of body weight per hour is 7-9 cubic meters. In the south, the larger value can be taken; in the north, the smaller value or the median value can be taken
11. It is hoped that the above calculation methods will be useful for everyone when designing and installing fans and cooling pads, for everyone's reference
1. Chicken house area: 120 m * 12 m = 1440 sq m
2. Chicken house cross-sectional area: 12 m * (height) 2.5 m = 30 sq m
3. Maximum total rearing weight in the chicken house: 1440 sq m * 12 birds/sq m * 2.5 kg/bird = 43200 kg
4. Required maximum ventilation rate: 43200 kg * 9 cubic meters per kg per hour = 388800 cubic meters
5. Number of fans required: 388800 cubic meters (divided by) assuming 43000 cubic meters per fan = 9 fans The ventilation rate of fans varies by model and manufacturer, so calculate according to actual fan parameters. Depending on the size of the chicken house, 1-3 backup fans need to be added. This chicken house needs at least 3 additional fans, so a total of 12 fans are required
6. Maximum air speed inside the house: 388800 cubic meters (divided by) 3600 seconds (divided by) cross-sectional area 30 sq m = 3.6 m per second
7. Cooling pad calculation: for 15 cm thickness, the required air speed through the pad is 1.5-2 m per second If the thickness is 10 cm, calculate the air speed through the pad as 1-1.5 m per second
8. Required cooling pad area: 388800 cubic meters (divided by) 3600 seconds (divided by) 1.5-2 m per second = 54—72 sq m Generally the median value is taken, requiring about 64 sq m of cooling pad area
9. The above calculation concerns negative pressure and the air leakage coefficient of the chicken house walls. With additional backup fans, it is sufficient.
10. The ventilation rate per kg of body weight per hour is 7-9 cubic meters. In the south, the larger value can be taken; in the north, the smaller value or the median value can be taken
11. It is hoped that the above calculation methods will be useful for everyone when designing and installing fans and cooling pads, for everyone's reference